---
title: Inference for Markov Chains
author: 36-467/36-667
date: 27 November 2018
bibliography: locusts.bib
output: slidy_presentation
---


\[
\newcommand{\Prob}[1]{\mathbb{P}\left( #1 \right)}
\newcommand{\Expect}[1]{\mathbb{E}\left[ #1 \right]}
\newcommand{\Var}[1]{\mathrm{Var}\left[ #1 \right]}
\newcommand{\transition}{\mathbf{q}}
\newcommand{\loglike}{L_n}
\newcommand{\TrueTransition}{\transition^*}
\newcommand{\InitDist}{p_{\mathrm{init}}}
\newcommand{InvDist}{p^*}
\]

```{r, include=FALSE}
library(knitr)
opts_chunk$set(size="small", background="white",
               cache=TRUE, autodep=TRUE,
               tidy=FALSE, warning=FALSE, message=FALSE,
               echo=TRUE)
options(np.messages=FALSE)
```

## In previous episodes...

- Markov process: future values of $X$ independent of past given current state $X(t)$
- Markov chains: Markov process with $X(t)$ discrete valued, say $k$ different states
- Transition matrix $\transition$, $q_{ij} = \Prob{X(t+1) = j| X(t) = i}$
    + $X(0)$ follows distribution $\InitDist$
- Invariant distribution $\InvDist$ is the left eigenvector of $\transition$ with eigenvalue 1
- Ergodicity: for a finite chain, distribution of $X_t$ converges on $\InvDist$, and time-averages converge on expectations w.r.t. $\InvDist$
    + Often ergodicity for continuous-valued Markov processes as well

## Inference for Markov Chains: Two Types of Data

- A whole trajectory or realization, $X(0), X(1), X(2), \ldots X(n)$
    + Multiple whole trajectories will work very similarly
- Aggregates:
    + There are $m$ processes all following the Markov chain, so $X_c(t)$ is state of process $c$ at time $t$, $c \in 1:m$
	+ We see $D_i(t) =$ number of processes in state $i$ at time $t$, $i \in 1:k$
	+ Don't get to observe whether process $c$ in particular has moved
- Individual-level data is much easier to deal with

## Likelihood for Markov Chains

- Assume individual-level data $x(0), \ldots x(n)$
- Using the Markov property, the likelihood is just
\[
\Prob{X(0) = x(0)} \prod_{t=0}^{n-1}{\Prob{X(t+1) = x(t+1)|X(t) = x(t)}} = \InitDist(x(0))\prod_{t=0}^{n-1}{ \transition_{x(t), x(t+1)}}
\]
- The log-likelihood is
\[
\log{\InitDist(x(0))} + \sum_{t=0}^{n-1}{\log{\transition_{x(t), x(t+1)}}}
\]
- Condition on $X(0)$, since it's uninformative about $\transition$:
\[
\loglike(\transition) \equiv \sum_{t=0}^{n-1}{\log{\transition_{x(t), x(t+1)}}}
\]
- Normalize, take the minus sign so we're minimizing:
\[
M_n(\transition) \equiv - \frac{1}{n} \sum_{t=0}^{n-1}{\log{\transition_{x(t), x(t+1)}}}
\]

## The Sufficient Statistics

- Define $N_{ij} \equiv$ number of times state $j$ follows state $i$ in the data
    + Define $N_i \equiv \sum_{j}{N_{ij}}$
- These are the **sufficient statistics**, because the likelihood only depends on the data through them:
\[
M_n = -\frac{1}{n}\sum_{i,j}{N_{ij}\log{\transition_{ij}}}
\]

## The Maximum Likelihood Estimate

- Minimize $M_n$ and get
\[
\hat{\transition}_{ij} = \frac{N_{ij}}{N_i}
\]
    + Need to ensure that each row of $\hat{\transition}$ adds to 1
	+ See handout on website
- By ergodic theorem,
\[
N_{ij}/n \rightarrow \InvDist_i \TrueTransition_{ij}
\]
- Therefore
\[
N_i/n \rightarrow \InvDist_i
\]
- Therefore
\[
\frac{N_{ij}}{N_i} = \frac{N_{ij}/n}{N_i/n} \rightarrow \frac{\InvDist_i \TrueTransition_{ij}}{\InvDist_i} = \TrueTransition_{ij}
\]


## Parameterized Markov Chains

- May not be able to vary all the transition probabilities separately
- May have an actual theory about how the transition probabilities are functions of underlying parameters
    + Compartment models exemplify both issues

Either way, $\transition$ is really $\transition(\theta)$, with $\theta$ the
$r$-dimensional vector of parameters
\[
\frac{\partial \loglike}{\partial \theta_u} = \sum_{ij}{\frac{\partial \loglike}{\partial \transition_{ij}}\frac{\partial \transition_{ij}}{\partial \theta_u}}
\]

## Inference for Parameterized Markov Chains

- Generally need Guttorp's "Conditions A"
    + which he got from @Billingsley-Markov (p. 23)

1. The allowed transitions are the same for all $\theta$
    + (technical convenience)
2. $\transition_{ij}(\theta)$ has continuous $\theta$-derivatives up to order 3
    + (authorizes Taylor expansions to 2nd order)
	+ (can sometimes get away with just 2nd partials)
3. The matrix $\partial \transition_{ij}/\partial \theta_u$ always has rank $r$
    + (no redundancy in the parameter space)
4. The chain is ergodic without transients for all $\theta$
    + ( trajectories are representative samples)

## Inference for Parameterized Markov Chains

- Assume all this, and that the chain was generated from $\theta=\theta^*$

1. MLE $\hat{\theta}$ exists
2. $\hat{\theta} \rightarrow \theta^*$ (consistency)
3. Asymptotic normality:
\[
\sqrt{n}\left(\hat{\theta} - \theta^*\right) \rightsquigarrow \mathcal{N}(0,I^{-1}(\theta^*))
\]
with \textbf{expected (Fisher) information}
\[
I_{uv}(\theta) \equiv \sum_{ij}{\frac{p_i(\theta)}{\transition_{ij}(\theta)}\frac{\partial \transition_{ij}}{\partial \theta_u}\frac{\partial \transition_{ij}}{\partial \theta_v}} = -\sum_{ij}{p_i(\theta)\transition_{ij}(\theta)\frac{\partial^2 \log{\transition_{ij}(\theta)}}{\partial \theta_u \partial \theta_v}}
\]
(2nd equality is not obvious)


## Error of the MLE

Error estimates based on $I(\theta^*)$ are weird: if you knew $\theta^*$, why
would you be calculating errors?

1. Plug-in: Use $I(\hat{\theta})$
2. Use the **observed information**
\[
J_{uv} = -\sum_{ij}{\frac{n_{ij}}{n}\frac{\partial^2 \log{\transition_{ij}(\hat{\theta})}}{\partial \theta_u \partial \theta_v}}
\]
    + (Guttorp's Eq.\ 2.207, but he's missing the sum over state pairs)
3. Use a parametric bootstrap
    + (Could use a block bootstrap if you think it's stationary)

## The Observed Information

\[
J_{uv} = -\frac{1}{n} \frac{\partial^2 \loglike(\hat{\theta})}{\partial \theta_u \partial \theta_v}
\]

- $nJ=$ how much the likelihood changes with a small change in parameters from
the maximum
- $J^{-1} =$ how much we can change the parameters before the
change in likelihood is noticeable
- If the model is right, then $J \rightarrow I(\hat{\theta})$, because both $\rightarrow I(\theta^*)$
- $\therefore$ use $J-I(\hat{\theta})$ to test for mis-specification [@White-specification-analysis]

## General Comment on Likelihood Inference for Markov Chains

- All of this is a special case of the general asymptotic theory from [Lectures 14](http://www.stat.cmu.edu/~cshalizi/dst/18/lectures/14/lecture-14.html) and [15](http://www.stat.cmu.edu/~cshalizi/dst/18/lectures/15/lecture-15.html)




## Higher-order Markov Chains

- Markov property: for all $t$,
\[
\Prob{X(t)|X(0), X(1), \ldots X(t-1)} = \Prob{X(t)|X(t-1)}
\]
- $m^{\mathrm{th}}$-order Markov: for all $t$,
\[
\Prob{X(t)|X(0), X(1), \ldots X(t-1)} = \Prob{X(t)|X(t-m), \ldots X(t-1)}
\]
- In a Markov chain, the _immediate_ state determines the distribution of future trajectories
- **Extended chain device**: Define $Y(t) = (X(t-m+1), \ldots X(t))$, and notice it's a first-order Markov chain
    + The likelihood theory is _exactly_ the same, only we need to condition on the first $k$ observations

## Hypothesis Testing

Likelihood-ratio testing is simple, for nested hypotheses:

- $\hat{\theta}_{\mathrm{small}}$ = MLE under the smaller, more restricted hypothesis
    + $d_{\mathrm{small}}$ parameters / degrees of freedom
- $\hat{\theta}_{\mathrm{big}}$ = MLE under larger hypothesis
    + d.o.f. $=d_{\mathrm{big}}$
- If the smaller hypothesis is true,
\[
\Lambda = 2[\loglike(\hat{\theta}_{\mathrm{big}}) - \loglike(\hat{\theta}_{\mathrm{small}})] \rightsquigarrow \chi^2_{d_{\mathrm{big}} - d_{\mathrm{small}}}
\]
which gives significance level
- If the bigger hypothesis is true, $\Lambda$ follows a non-central $\chi^2$ distribution
    + Can be used to calculate power, or just simulate

## Hypothesis Testing (cont'd)

- What about small $n$?  Distribution won't have converged
- Use parametric bootstrapping again:

1. Calculate log likelihood ratio $\Lambda$ on real data, call this $\lambda$
2. Simulate from $\hat{\theta}_{\mathrm{small}}$, get fake data $Y_1^n$
3. Estimate $\tilde{\theta}_{\mathrm{small}}$, $\tilde{\theta}_{\mathrm{big}}$
from $Y_1^n$
4. Calculate $\tilde{\Lambda}$ from $\tilde{\theta}_{\mathrm{small}}$, $\tilde{\theta}_{\mathrm{big}}$
5. Repeat (2)--(4) $B$ times to get sample of $\tilde{\Lambda}$
6. $p$-value = $\#\left\{\tilde{\Lambda} \geq \lambda\right\}/B$

- Getting power is similar but simulate from $\hat{\theta}_{\mathrm{big}}$

n## Examples

- Testing parametrized transition matrices:
    + d.o.f. $=k(k-1)$ for a first-order chain
    + d.o.f. $=k^m(k-1)$ for a $k$-order chain
    + fixed transition matrix, or fixed $\theta^*$, has d.o.f. $=0$
	+ otherwise the parameterized transitions have d.o.f. $=r$
- Lower-order chains are nested inside higher-order chains, so you can test for
order restrictions

## Aggregates

- Individuals $X_i(t)$, $i \in 1:m$, all following transition matrix $\transition$
- We see $D_i(t) =$ count of individuals in state $i$ at time $t$
    + $D(t) =$ vector of all $D_i(t)$
- Exercise 1: Find $\Expect{D_j(t+1)|D(t)}$, in terms of the $D_i(t)$ and $\transition$
- Exercise 2: Find $\Var{D_j(t+1)|D(t)}$, in terms of the $D_i(t)$ and $\transition$
    + Assume independent transitions

## Aggregates [@Kalbfleisch-Lawless-markov-from-aggregate]

- $D_i(t) =$ count of individuals in state $i$ at time $t$
    + $D(t) =$ vector of all $D_i(t)$
- $\sum_{i}{\transition_{ij} D_i(t)}= \Expect{D_j(t+1)|D(t)}$
    + Because each of the $D_i(t)$ individuals moves to state $j$ with probability $\transition_{ij}$
- $\sum_{i}{\transition_{ij}(1-\transition_{ij})D_i(t)}= \Var{D_j(t+1)|D(t)}$
    + Similarly for the variance
- Linearly regress $D_j(t+1)$ on $D(t)$
    + Slope on $D_i(t)$ is $\transition_{ij}$
    + No intercept (why?)
	+ Using weighted least squares with inverse-variance weights gives more precise estimates


## Continuous-Valued Processes in Discrete Time

- Instead of a transition matrix, have a transition **density** or **kernel**,
i.e., a conditional pdf $\transition(x,y) = p(X(t+1) = y|X(t) =x)$
- If this is parameterized, $\transition(x,y;\theta)$, can do the MLE as
usual
    + Replace sums above with integrals
- What if we want non-parameteric estimates?

## Nonparametric Density Estimation

- Introduce a **kernel** $K(u)$, a pdf for $X$
    + Usually require $\int{u K(u) du} = 0$, $0 < \int{u^2 K(u) du} < \infty$
- $\frac{1}{h}K\left(\frac{x-x_i}{h}\right)$ is a pdf centered at $x_i$, with **bandwidth** $h$
- If $X_1, X_2, \ldots X_n$ have pdf $p$, then
\[
\hat{p}_n(x) = \frac{1}{nh}\sum_{i=1}^{n}{K\left(\frac{x-x_i}{h}\right)}
\]
is a non-parametric estimate of $p$
    + Need to let $h \rightarrow 0$ as $n\rightarrow \infty$
- Pick $h$ by cross-validation
    + Want high log-likelihood for unseen data

## Nonparametric Conditional Density Estimation

- Remember $p(X(t+1)=y|X(t)=x) = p(X(t)=x, X(t+1)=y)/p(X(t)=x)$
- Estimate by
\[
\hat{\transition}(x,y) = \frac{\frac{1}{(n-1) h_1 h_2}\sum_{t=1}^{n}{K\left(\frac{x-x(t-1)}{h_1}\right) K\left(\frac{y-x(t)}{h_2}\right)}}{\frac{1}{(n-1) h_1}\sum_{t=1}^{n}{K\left(\frac{x-x(t-1)}{h_1}\right)}}
\]
- Again, pick both $h_1$ and $h_2$ to get high conditional log-likelihood on
unseen data
    + See @Hall-Racine-Li-CV
- Higher-order processes work similarly


## Example: Lynxes

```{r}
data(lynx)
lynx.lagged <- data.frame(t0=head(lynx,-1), t1=tail(lynx,-1))
plot(t1~t0, data=lynx.lagged, xlab="X(t)", ylab="X(t+1)", main="Canadian Lynxes")
```

## Examples: Lynxes

- The `np` library lets us estimate conditional densities with the `npcdens` function

```{r}
library(np)
lynx.trans <- npcdens(t1 ~ t0, data=lynx.lagged)
plot(lynx.trans, view="fixed", phi=45, theta=30,
     xlab="X(t)", ylab="X(t+1)", zlab="p(X(t+1)=y|X(t)=x)") # Default is a rotating visualization
```


## Summary

- Maximum likelihood for chains is natural and efficient
    + Even for parameterized models
- Model checking / hypothesis testing is very much as in the IID case
- For continuous processes, use conditional density estimation

## Backup: Smoothing the MLE for Large State Spaces

- MLE says $\hat{\transition}_{ij} = 0$ iff $N_{ij}=0$
- If the state space is large, $N_{ij}$ might be zero just because we haven't had time to see that transition
- One solution: fictitious counts
- Fix $\mu > 0$, and set
\[
\tilde{\transition}_{ij} = \frac{N_{ij}+\mu}{\sum_{j}{(N_{ij}+\mu)}}
\]
- If $\mu$ is fixed as $n\rightarrow\infty$,
\[
\frac{N_{ij}+\mu}{\sum_{j}{(N_{ij}+\mu)}} = \frac{N_{ij}/n + \mu/n}{N_i/n + k\mu/n} \rightarrow \TrueTransition_{ij}
\]
- Can pick $\mu$ by some estimate of how much we've under-sampled
- Or by cross-validation
- Refinement: Different $\mu_j$ for each $j$, perhaps reflecting $N_j$

## Backup: Smoothing the MLE for Language Models {.smaller}

- Markov chains for text typically have words for states
    + Sometimes do letters or sounds (phonemes) for spelling, predictive text, speech recognition...
    + Markov actually did a model of letters (vowels vs. consonants)
	+ but usually words
- Languages have large vocabularies
    + Say $10^4$ words at the low end to $10^6$ at the high end
	+ Depends on language, how you count "word", etc.
- So languages have even larger numbers of word sequences
    + $10^8$ to $10^{12}$ for pairs
	+ Even more for higher-order chains
	+ A decent-length book is only $10^5$ words, so even a corpus of $10^3$ books can't cover the state space
- Detailed example of making this work at scale: @Pereira-Singer-Tishby-beyond-n-grams

## Backup: Markov Chains with Countably-Infinite State Spaces

- The MLE is still $\hat{\transition}_{ij} = N_{ij}/N_i$
- Problem: This gives 0 probability to visiting states outside the data
- Solutions:
    + Parameterize the transition probabilities
	+ Replace the MLE with something else
- Outstanding example of "something else":
    + Pick $\mu_j$ such that $\mu_j > 0$, $\sum_{j}{\mu_j} < \infty$
	+ Set $\hat{\transition}_{ij} \propto (N_{ij} + \mu_j)$
	+ Can you work out what the denominator needs to be?


## Backup: Markov Chains in Continuous Time

- $X(t)$ takes only discrete values, with jumps at times $t_1, t_2, \ldots t_n$
- Need $\Prob{X(t+h)=j|X(t)=i} = \transition(h)$ for all $h$
- Consistency condition: $\transition_{ij}(h_1+h_2) = \sum_{k}{\transition_{ik}(h_1)\transition_{kj}(h_2)}$
    + a.k.a. **Chapman-Kolmogorov equation**
- This forces $\transition(h) = e^{h\mathbf{g}}$
	+ Read this as $\transition(h) = \sum_{r=0}^{\infty}{\frac{1}{r!}(h\mathbf{g})^r}$
    + Matrix $\mathbf{g}$ is called the **generator** of the transition matrices $\transition(h)$
	+ If $h\approx 0$, $\transition(h) \approx \mathbf{I} + h\mathbf{g}$
- Can do full likelihood-based inference (see Guttorp)
- _or_ discretize time at some small $h$, get $\hat{\transition}(h)$, and back out $\hat{\mathbf{g}}$


## Backup: Further reading

- _Everyone_ steals the theory of likelihood inference for Markov chains from @Billingsley-Markov
- @Guttorp-scientific is easier reading, and excerpts are on Canvas

## References
